# Model Question Paper-3 Class-8 ML Aggarwal Solutions

Model Questions Paper-3 Class-8 ML Aggarwal ICSE Mathematics Solutions. APC Understanding Mathematics for ICSE Class-8 Model Question Paper-3 Solutions of Section-A , B, C and D based on Chapter-1 to 9. Visit official Website **CISCE **for detail information about ICSE Board Class-8 Mathematics.

## Model Questions Paper-3 Class-8 ML Aggarwal ICSE Mathematics Solutions

( Based on chapter-1 to 9)

Time Allowed-2 and 1/2 hour

max mark-90

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**Section-A , Paper-3 Class-8 ML Aggarwal**

**Questions 1 to 8 are of 1 mark each.**

Question 1.

Product of rational number and its additive inverse is

(a)

(b)

(c) 1

(d) 0

#### Answer

Product of rational number and its

additive inverse –

= (b)

Question 2.

What should be subtracted from to get ?

#### Answer

Question 3.

The value of is

#### Answer

Question 4.

Standard form of 0.00000000234 is

(a) 2.34 × 10^{-8}

(b) 23.4 × 10^{-10}

(c) 2.34 × 10^{-9}

(d) 234 × 10^{-1}

#### Answer

0.00000000234 = 2.34 × 10^{-9} (c)

Question 5.

The volume of a cube is 216 m^{3}. Length of its side is

(a) 3 m

(b) 6 m

(c) 9 m

(d) 12 m

#### Answer

Volume of a cube = 216 m^{3}

∴ Side – = 6 m (b)

Question 6.

When the difference of a 2-digit number ab (a > b) and the number obtained by reversing the digits is divided by 9, then quotient is

(a) a + b

(b) b – a

(c) a – b

(d) none of these

#### Answer

The difference of the two-digit number ab (a > b)

and the number reversing the digits = = a – b (c)

Question 7.

Amar buys a toy for ₹ 120 and sells it for ₹ 144, his profit % is

(a) 5%

(b) 10%

(c) 20%

(d) 24%

#### Answer

C.P. of a toy = ₹120

S.P. = ₹144

∴ Profit = S.P. – C.P. = ₹144 – ₹120 = ₹24

and Profit % = = 20% (c)

Question 8.

If 567×8 is divisible by 9, then value of x is

(a) 1

(b) 2

(c) 3

(d) 4

#### Answer

∵ 576×8 is divisible by 9

∴ Sum of digits 8 + x + 7 + 6 + 5 is also divisible by 9

⇒ 26 + x is divisible by 9

⇒ 26 + x = 27

⇒ x = 27 – 26 = 1

∴ x = 1

** Paper-3 Class-8 ML Aggarwal ****Section-B**

**Questions 9 to 14 are of 2 marks each.**

**
**Question 9.

Ramesh bought a fan for ₹ 1320 including 10% VAT. Find the price of the fan before VAT was added.

#### Answer

Value of a fan including VAT = ₹1320

VAT = 10%

∴ Price of the fan before adding VAT

Question 10.

Find A in the addition

#### Answer

A + 5 = 2 or 12

∴ A = 12 – 5 = 7

Question 11.

Find the value of x for which .

#### Answer

Question 12.

Using appropriate properties of operations of rational numbers, evaluate:

#### Answer

Question 13.

What number should be subtracted from the sum of and to get ?

#### Answer

Question 14.

If n(ξ) = 40, n(A) = 23, n(B’) = 28 and n(A ∪ B’) = 9, find n(A ∩ B).

#### Answer

n(ξ) = 40, n(A) = 23, n(B’) = 28

n(A ∪ B’) = 9

n(B) – n(ξ) = -n(B’)

= 40 – 28 = 12

n(A ∪ B) = n(ξ) – n(A ∪ B)’ = 40 – 9 = 31

∴ n(A ∩ B) = n(A) + n(B) – n(A ∪ B)

= 23 + 12 – 31 = 35 – 31 = 4

**Section-C, Model Question ****Paper-3 Class-8 ML Aggarwal Solutions**

**Questions 15 to 24 are of 4 marks each.**

Question 15.

In an auditorium, the number of rows is equal to the number of chairs in each row. If there are 5184 chairs in the auditorium, find the number of rows.

#### Answer

In an auditorium number of rows = number of chairs in a row

Total chairs = 5184

Number of rows = = 72

Question 16.

Insert 5 rational numbers between and .

#### Answer

5 rational numbers between and

LCM of 3, 2 = 6

Question 17.

Find the smallest number by which 10584 should be multiplied so that product is a perfect cube. Also find the cube root of the product.

#### Answer

10584

Factors of 10584

= 2 × 2 × 2 × 3 × 3 × 3 × 7 × 7

Grouping the same factors in triplet, 7 × 7 are left unpaired.

∴ In order to complete a perfect cube, we shall multiply by 7.

So product = 10584 × 7 = 74088 and cube root = 2 × 3 × 7 = 42

Question 18.

In a 3-digit number unit’s digit is 2 less than hundred’s digit and hundred’s digit is 3 less than the ten’s digit. If the sum of the original number and number obtained by reversing the digits is 968, find the number.

#### Answer

In a 3-digit number,

Let tens digit = x

Then hundreds, digit = x – 3

and unit digit = x – 3 – 2 = x – 5

∴ Number = (x – 5) + 10(x) + 100(x – 3)

= x – 5 + 10x + 100x – 300

= 111x – 305

By reversing the digits

Unit digit = x – 3

Ten’s digit = x

and hundred’s digit = x – 5

∴ Number = x – 3 + 10x + 100x – 500 = 111x – 503

According to the condition,

111x – 305 + 111x – 503 = 968

⇒ 222x – 808 = 968

222x = 968 + 808 = 1776

x = = 8

and hundred’s digit = x – 5

∴ Number = 111 × 8 – 305 = 888 – 305 = 583

Question 19.

Rohit purchased some oranges at 3 for ₹5 and sold them at 5 for ₹12. Thus he gained ₹143 in all. How many oranges did he purchase?

#### Answer

LCM of 3, 5 = 15

Let Rohit purchased = 15 oranges

∴ C.R of 15 oranges = × 5 = ₹25

and S.R of 15 oranges = × 12 = ₹36

Gain = S.P. – C.P. = ₹36 – ₹25 = ₹11

If gain is ₹11, then number apples = 15

and if gain is ₹143, then number of apples = × 143 = 195

Question 20.

How much per cent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 20% he still earns a profit of 20%?

#### Answer

Let cost price = ₹100

Profit = 20%

∴ He should marked price ₹(150 – 100) = 50% above the cost price

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